Complex Roots Calculator: All Roots of a Complex Number
Find every n-th root of a complex number. The default solves z to the power 6 equals 1, which has six solutions.
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How this calculator works
Write the number in polar form with a size r and an angle. The n-th roots all have size r to the power one over n, and their angles are the original angle plus a whole turn for each k, all divided by n.
This gives n different roots, evenly spaced round a circle. For z to the power 6 equal to 1 the roots are at 0, 60, 120, 180, 240 and 300 degrees.
Formulas used
- z_k = r^{1/n}\,e^{i(\theta + 2\pi k)/n}
- k = 0, 1, \ldots, n-1
Worked example
With the default numbers in the calculator above:
- The number in polar form: 1.00 at 0.00 °
- Size of every root: 1.00
- Angle between neighbouring roots: 60.00 °
- Root k = 0: 1.00 + 0.00i (at 0.00 °)
- Root k = 1: 0.50 + 0.87i (at 60.00 °)
- Root k = 2: -0.50 + 0.87i (at 120.00 °)
- Root k = 3: -1.00 + 0.00i (at 180.00 °)
- Root k = 4: -0.50 - 0.87i (at 240.00 °)
- Root k = 5: 0.50 - 0.87i (at 300.00 °)
- Check: the roots add up to zero: 0.00 + 0.00i
Change the numbers in the calculator to see the full working, every step, for your own case.
A second worked example
A different case, with these numbers: Real part of the number -8; Imaginary part of the number 0; Which root? (the power n) 3.
- The number in polar form: 8.00 at 180.00 °
- Size of every root: 2.00
- Angle between neighbouring roots: 120.00 °
- Root k = 0: 1.00 + 1.73i (at 60.00 °)
- Root k = 1: -2.00 + 0.00i (at 180.00 °)
- Root k = 2: 1.00 - 1.73i (at 300.00 °)
- Check: the roots add up to zero: 0.00 + 0.00i
Common questions
How many solutions does z^6 = 1 have?
Six. Two of them are real (1 and -1) and four are complex.
Why do the roots add up to zero?
They are spread evenly round a circle, so they cancel each other out.
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Got a question about this? Ask an engineering question and get a plain-language answer with references.
Further reading: Standard algebra and complex number texts (De Moivre theorem and roots of unity).
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